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6x^2=-21x+12
We move all terms to the left:
6x^2-(-21x+12)=0
We get rid of parentheses
6x^2+21x-12=0
a = 6; b = 21; c = -12;
Δ = b2-4ac
Δ = 212-4·6·(-12)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-27}{2*6}=\frac{-48}{12} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+27}{2*6}=\frac{6}{12} =1/2 $
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